Gönderen Konu: TORQUE vs HP (ingilizce-Türkçe)  (Okunma sayısı 3784 defa)


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TORQUE vs HP (ingilizce-Türkçe)
« : Aralık 12, 2005, 10:55:02 ÖS »
Force, Work and Time
If you have a one pound weight bolted to the floor, and try to lift it with one pound of force (or 10, or 50 pounds), you will have applied force and exerted energy, but no work will have been done. If you unbolt the weight, and apply a force sufficient to lift the weight one foot, then one foot pound of work will have been done. If that event takes a minute to accomplish, then you will be doing work at the rate of one foot pound per minute. If it takes one second to accomplish the task, then work will be done at the rate of 60 foot pounds per minute, and so on.

In order to apply these measurements to automobiles and their performance (whether you're speaking of torque, horsepower, newton meters, watts, or any other terms), you need to address the three variables of force, work and time.

Awhile back, a gentleman by the name of Watt (the same gent who did all that neat stuff with steam engines) made some observations, and concluded that the average horse of the time could lift a 550 pound weight one foot in one second, thereby performing work at the rate of 550 foot pounds per second, or 33,000 foot pounds per minute, for an eight hour shift, more or less. He then published those observations, and stated that 33,000 foot pounds per minute of work was equivalent to the power of one horse, or, one horsepower.

Everybody else said OK. :-)

For purposes of this discussion, we need to measure units of force from rotating objects such as crankshafts, so we'll use terms which define a *twisting* force, such as foot pounds of torque. A foot pound of torque is the twisting force necessary to support a one pound weight on a weightless horizontal bar, one foot from the fulcrum.

Now, it's important to understand that nobody on the planet ever actually measures horsepower from a running engine. What we actually measure (on a dynamometer) is torque, expressed in foot pounds (in the U.S.), and then we *calculate* actual horsepower by converting the twisting force of torque into the work units of horsepower.

Visualize that one pound weight we mentioned, one foot from the fulcrum on its weightless bar. If we rotate that weight for one full revolution against a one pound resistance, we have moved it a total of 6.2832 feet (Pi * a two foot circle), and, incidentally, we have done 6.2832 foot pounds of work.

OK. Remember Watt? He said that 33,000 foot pounds of work per minute was equivalent to one horsepower. If we divide the 6.2832 foot pounds of work we've done per revolution of that weight into 33,000 foot pounds, we come up with the fact that one foot pound of torque at 5252 rpm is equal to 33,000 foot pounds per minute of work, and is the equivalent of one horsepower. If we only move that weight at the rate of 2626 rpm, it's the equivalent of 1/2 horsepower (16,500 foot pounds per minute), and so on. Therefore, the following formula applies for calculating horsepower from a torque measurement:

                                Torque * RPM
        Horsepower      =       ------------

This is not a debatable item. It's the way it's done. Period.

The Case For Torque
Now, what does all this mean in carland?

First of all, from a driver's perspective, torque, to use the vernacular, RULES :-). Any given car, in any given gear, will accelerate at a rate that *exactly* matches its torque curve (allowing for increased air and rolling resistance as speeds climb). Another way of saying this is that a car will accelerate hardest at its torque peak in any given gear, and will not accelerate as hard below that peak, or above it. 300 foot pounds of torque will accelerate you just as hard at 2000 rpm as it would if you were making that torque at 4000 rpm in the same gear, yet, per the formula, the horsepower would be *double* at 4000 rpm.

In contrast to a torque curve (and the matching pushback into your seat), horsepower rises rapidly with rpm, especially when torque values are also climbing. Horsepower will continue to climb, however, until well past the torque peak, and will continue to rise as engine speed climbs, until the torque curve really begins to plummet, faster than engine rpm is rising. However, as I said, horsepower has nothing to do with what a driver *feels*.

You don't believe all this?

Fine. Take your non turbo car (turbo lag muddles the results) to its torque peak in first gear, and punch it. Notice the belt in the back? Now take it to the power peak, and punch it. Notice that the belt in the back is a bit weaker? Fine. Can we go on, now? :-)

The Case For Horsepower
OK. If torque is so all-fired important, why do we care about horsepower?

Because (to quote a friend), "It is better to make torque at high rpm than at low rpm, because you can take advantage of *gearing*.

For an extreme example of this, I'll leave carland for a moment, and describe a waterwheel I got to watch awhile ago. This was a pretty massive wheel (built a couple of hundred years ago), rotating lazily on a shaft which was connected to the works inside a flour mill. Working some things out from what the people in the mill said, I was able to determine that the wheel typically generated about 2600(!) foot pounds of torque. I had clocked its speed, and determined that it was rotating at about 12 rpm. If we hooked that wheel to, say, the drive wheels of a car, that car would go from zero to twelve rpm in a flash, and the waterwheel would hardly notice :-).

On the other hand, twelve rpm of the drive wheels is around one mph for the average car, and, in order to go faster, we'd need to gear it up. To get to 60 mph would require gearing the wheel up enough so that it would be effectively making a little over 43 foot pounds of torque at the output, which is not only a relatively small amount, it's less than what the average car would need in order to actually get to 60. Applying the conversion formula gives us the facts on this. Twelve times twenty six hundred, over five thousand two hundred fifty two gives us:

6 HP.

Oops. Now we see the rest of the story. While it's clearly true that the water wheel can exert a *bunch* of force, its *power* (ability to do work over time) is severely limited.

At The Dragstrip
OK. Back to carland, and some examples of how horsepower makes a major difference in how fast a car can accelerate, in spite of what torque on your backside tells you :-).

A very good example would be to compare the current LT1 Corvette with the last of the L98 Vettes, built in 1991. Figures as follows:

        Engine          Peak HP @ RPM   Peak Torque @ RPM
        ------          -------------   -----------------
        L98             250 @ 4000      340 @ 3200
        LT1             300 @ 5000      340 @ 3600

The cars are geared identically, and car weights are within a few pounds, so it's a good comparison.

First, each car will push you back in the seat (the fun factor) with the same authority - at least at or near peak torque in each gear. One will tend to *feel* about as fast as the other to the driver, but the LT1 will actually be significantly faster than the L98, even though it won't pull any harder. If we mess about with the formula, we can begin to discover exactly *why* the LT1 is faster. Here's another slice at that formula:

                                Horsepower * 5252
                Torque  =       -----------------

If we plug some numbers in, we can see that the L98 is making 328 foot pounds of torque at its power peak (250 hp @ 4000), and we can infer that it cannot be making any more than 263 pound feet of torque at 5000 rpm, or it would be making more than 250 hp at that engine speed, and would be so rated. In actuality, the L98 is probably making no more than around 210 pound feet or so at 5000 rpm, and anybody who owns one would shift it at around 46-4700 rpm, because more torque is available at the drive wheels in the next gear at that point.

On the other hand, the LT1 is fairly happy making 315 pound feet at 5000 rpm, and is happy right up to its mid 5s redline.

So, in a drag race, the cars would launch more or less together. The L98 might have a slight advantage due to its peak torque occurring a little earlier in the rev range, but that is debatable, since the LT1 has a wider, flatter curve (again pretty much by definition, looking at the figures). From somewhere in the mid range and up, however, the LT1 would begin to pull away. Where the L98 has to shift to second (and throw away torque multiplication for speed), the LT1 still has around another 1000 rpm to go in first, and thus begins to widen its lead, more and more as the speeds climb. As long as the revs are high, the LT1, by definition, has an advantage.

Another example would be the LT1 against the ZR-1. Same deal, only in reverse. The ZR-1 actually pulls a little harder than the LT1, although its torque advantage is softened somewhat by its extra weight. The real advantage, however, is that the ZR-1 has another 1500 rpm in hand at the point where the LT1 has to shift.

There are numerous examples of this phenomenon. The Integra GS-R, for instance, is faster than the garden variety Integra, not because it pulls particularly harder (it doesn't), but because it pulls *longer*. It doesn't feel particularly faster, but it is.

A final example of this requires your imagination. Figure that we can tweak an LT1 engine so that it still makes peak torque of 340 foot pounds at 3600 rpm, but, instead of the curve dropping off to 315 pound feet at 5000, we extend the torque curve so much that it doesn't fall off to 315 pound feet until 15000 rpm. OK, so we'd need to have virtually all the moving parts made out of unobtanium :-), and some sort of turbocharging on demand that would make enough high-rpm boost to keep the curve from falling, but hey, bear with me.

If you raced a stock LT1 with this car, they would launch together, but, somewhere around the 60 foot point, the stocker would begin to fade, and would have to grab second gear shortly thereafter. Not long after that, you'd see in your mirror that the stocker has grabbed third, and not too long after that, it would get fourth, but you'd wouldn't be able to see that due to the distance between you as you crossed the line, *still in first gear*, and pulling like crazy.

I've got a computer simulation that models an LT1 Vette in a quarter mile pass, and it predicts a 13.38 second ET, at 104.5 mph. That's pretty close (actually a tiny bit conservative) to what a stock LT1 can do at 100% air density at a high traction drag strip, being powershifted. However, our modified car, while belting the driver in the back no harder than the stocker (at peak torque) does an 11.96, at 135.1 mph, all in first gear, of course. It doesn't pull any harder, but it sure as hell pulls longer :-). It's also making *900* hp, at 15,000 rpm.

Of course, folks who are knowledgeable about drag racing are now openly snickering, because they've read the preceding paragraph, and it occurs to them that any self respecting car that can get to 135 mph in a quarter mile will just naturally be doing this in less than ten seconds. Of course that's true, but I remind these same folks that any self-respecting engine that propels a Vette into the nines is also making a whole bunch more than 340 foot pounds of torque.

That does bring up another point, though. Essentially, a more "real" Corvette running 135 mph in a quarter mile (maybe a mega big block) might be making 700-800 foot pounds of torque, and thus it would pull a whole bunch harder than my paper tiger would. It would need slicks and other modifications in order to turn that torque into forward motion, but it would also get from here to way over there a bunch quicker.

On the other hand, as long as we're making quarter mile passes with fantasy engines, if we put a 10.35:1 final-drive gear (3.45 is stock) in our fantasy LT1, with slicks and other chassis mods, we'd be in the nines just as easily as the big block would, and thus save face :-). The mechanical advantage of such a nonsensical rear gear would allow our combination to pull just as hard as the big block, plus we'd get to do all that gear banging and such that real racers do, and finish in fourth gear, as God intends. :-)

The only modification to the preceding paragraph would be the polar moments of inertia (flywheel effect) argument brought about by such a stiff rear gear, and that argument is outside of the scope of this already massive document. Another time, maybe, if you can stand it :-).

At The Bonneville Salt Flats
Looking at top speed, horsepower wins again, in the sense that making more torque at high rpm means you can use a stiffer gear for any given car speed, and thus have more effective torque *at the drive wheels*.

Finally, operating at the power peak means you are doing the absolute best you can at any given car speed, measuring torque at the drive wheels. I know I said that acceleration follows the torque curve in any given gear, but if you factor in gearing vs car speed, the power peak is *it*. An example, yet again, of the LT1 Vette will illustrate this. If you take it up to its torque peak (3600 rpm) in a gear, it will generate some level of torque (340 foot pounds times whatever overall gearing) at the drive wheels, which is the best it will do in that gear (meaning, that's where it is pulling hardest in that gear).

However, if you re-gear the car so it is operating at the power peak (5000 rpm) *at the same car speed*, it will deliver more torque to the drive wheels, because you'll need to gear it up by nearly 39% (5000/3600), while engine torque has only dropped by a little over 7% (315/340). You'll net a 29% gain in drive wheel torque at the power peak vs the torque peak, at a given car speed.

Any other rpm (other than the power peak) at a given car speed will net you a lower torque value at the drive wheels. This would be true of any car on the planet, so, theoretical "best" top speed will always occur when a given vehicle is operating at its power peak.

"Modernizing" The 18th Century
OK. For the final-final point (Really. I Promise.), what if we ditched that water wheel, and bolted an LT1 in its place? Now, no LT1 is going to be making over 2600 foot pounds of torque (except possibly for a single, glorious instant, running on nitromethane), but, assuming we needed 12 rpm for an input to the mill, we could run the LT1 at 5000 rpm (where it's making 315 foot pounds of torque), and gear it down to a 12 rpm output. Result? We'd have over *131,000* foot pounds of torque to play with. We could probably twist the whole flour mill around the input shaft, if we needed to :-).

The Only Thing You Really Need to Know
 "It is better to make torque at high rpm than at low rpm, because you can take advantage of *gearing*."

Alıntı yapılan: "C.E.M"
Güç ve Tork İlişkisi

Güç ve tork ilişkisi çoğu zaman birçok kişi için karışık gelir. Otomobilleri kıyaslarken bu iki terimi sık sık kullanıyoruz ama çoğumuz hangisinin daha önemli olduğunu bırakın, tam olarak ne anlama geldiğini bile bilmiyoruz. Eski bir söz vardır : Tork katılım kazandırır, güç otomobil sattırır. Bu gerçekten doğru mu? İşte bu yazımızda bu iki başlığı açıklığa kavuşturacağız.

Özetle, güç ve tork tamamen ayrı şeylerdir ve ölçü birimleri de birbirinden farklıdır.

Tork : Tork döndürme kuvvetidir. Hareket ve zamandan bağımsız bir kavram olan torkun ölçü birimi Nm (Newton*metre) dir. Tork bir kol yardımı ile sabit, dönen bir noktaya kuvvet etki ettiğinde yaratılır. Sabit, dönen bir noktaya 1 metre uzunluğunda bir kol yardımı ile 1 Newton (1/9.8 kg. - 9.8 N = 1 kg.) kuvvet uyguladığımızda 1 Nm tork doğar. Otomobillerde tork krank milinde doğar. Şanzıman üzerinden çekiş tekerinin olduğu aksa kadar ilerler ve aksta bağlı bulunan tekerlekler ile yola doğrusal bir kuvvet olarak aktarılır. Tekerleklerin yere aktardığı doğrusal kuvvetli, çekiş tekerinin olduğu aksa iletilen torku bilmek suretiyle kolayca hesaplayabiliriz.

Doğrusal kuvvet = (aksa iletilen tork) / (tekerleğin yarıçapı)

Bir motorun ürettiği tork motorun devrine göre değişir ve grafikte bir eğri ile gösterilir. Bu eğriyi her devirde anlık olarak ölçülmüş tork değerlerini belirten noktalar oluşturur. Sürüş anındaki güç kayıpları göz ardı edilerek krank milindeki torkun, otomobili ilerleten doğrusal kuvvetle herhangi bir viteste her zaman doğru orantılı olduğunu söyleyebiliriz. Tam düz bir tork "eğrisi" olsaydı otomobil hangi viteste, hangi devirde olursa olsun, sabit ivme ile hızlanırdı. Ancak gerçek hayatta tork "eğrileri" düz değildir. tavan yapmak üzere yükselirler ve çok yüksek devirlerde yine düşerler. Bir otomobil, motoru (herhangi bir viteste) en yüksek torkunu verdiği devirde seyrettiği zaman en iyi şekilde hızlanır. Dikkat edin, en iyi hızlanmanın nasıl sağlanacağını belirledik ve daha beygirgücünden bahsetmedik bile.

Güç : Güç, iş yapma oranıdır ve ölçü birimi W (Watt) dır. Torkun aksine güç, zaman ve hareken kavramlarına bağımlıdır. Güç ve tork arasında direk bir bağlantı gösterebiliriz. Bir otomobilin ürettiği güç, motorun çevirdiği devre bağlı olarak değişir ve tipik olarak grafikte bir eğri ile gösterilir. Güç ve tork arasındaki bağıntıyı formüle dökmek gerekirse :

Güç = Tork * (o tork değerinin üretildiği devir) / 5252

Not: Bu formül, sadece, tork lbf, güç de HP cinsinden birimlendirildiğinde geçerlidir.

Bu noktaya kadar öğrendiklerimizi özetleyecek olursak :

- Otomobilin ivmelenmesi, akstaki torkun tekerlekte doğrusal kuvvete dönüşmesidir.
- Herhangi bir viteste en iyi ivme, motorun en yüksek torku ürettiği devirde sağlanır.
- Güç, tork ve devre bağlı bir fonksiyondur.
Eğer bu noktada gücün önemsiz olduğuna karar kıldıysanız yanılıyorsunuz. Lütfen okumaya devam edin.

Şanzıman, otomobilin ivmelenmesindeki en önemli etkendir. Güç ve tork arasındaki ilişkiyi anlatmak ve gücün de yazının bu ana kadarki bölümünde anlatılan kadar önemsiz olmadığını göstermek için, hipotez olarak, birinci vitesi 2:1 oranlı, ikinci vitesi de 1:1 oranlı iki vitesli bir şanzıman ele alalım. Ve bun şanzımanı yine hipotez olarak her devirde, krank milinde 100 Nm tork üreten bir motora bağlayalım.

1:1 oranlı ikinci vites, sürüş milini krank miliyle aynı hızda çevirir ve tam olarak 100 Nm kuvvet yere iletilir (Sürtünme kuvvetlerinin olmadığını var sayıyoruz.). Ancak 2:1 oranlı birinci vites sürüş milini krank milinin katılımı kadar bir hızla çevirir ve krank milinin ürettiği gücün iki katı yani 200 Nm kuvvet yere iletilir. Dolayısıyla otomobilimiz birinci viteste, ikinci viteste olduğundan iki kat daha iyi ivmelenir. İşte bu noktada da beygirgücünün önemini anlatan anahtar yatar. Vites küçültme suretiyle, tekerleklere iletilen maksimum tork (belli bir hız için), otomobilin motoru en yüksek gücü ürettiği devirde çalışırken sağlanır.

Tork çarpımının sonucu olarak diyebiliriz ki, bir otomobil, herhangi bir devirde, motoru en yüksek gücü ürettiği devre getiren bir vites seçildiğinde en iyi şekilde hızlanır. Bu da yüksek devir çeviren küçük motorların, fazla devir çeviremeyen büyük motorlardan bazen üstün oluşlarının sebebidir. Yüksek devirler çevirebilen bir motorda, kranka aktarılan tork az olmasına rağmen tork çarpımı sayesinde tekerleklere çok daha yüksek tork değerleri aktarılabilir.


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TORQUE vs HP (ingilizce-Türkçe)
« Yanıtla #1 : Aralık 13, 2005, 09:10:27 ÖÖ »
cok güzel açıklamışsın tebrik ederim.. :D


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TORQUE vs HP (ingilizce-Türkçe)
« Yanıtla #2 : Aralık 13, 2005, 10:10:54 ÖÖ »
Okumam uzun sürdü ama değdi, eline sağlık


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TORQUE vs HP (ingilizce-Türkçe)
« Yanıtla #3 : Aralık 15, 2005, 12:29:33 ÖÖ »
Updated ;)